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(46)^2=4x^2=2116
We move all terms to the left:
(46)^2-(4x^2)=0
We add all the numbers together, and all the variables
-4x^2+2116=0
a = -4; b = 0; c = +2116;
Δ = b2-4ac
Δ = 02-4·(-4)·2116
Δ = 33856
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{33856}=184$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-184}{2*-4}=\frac{-184}{-8} =+23 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+184}{2*-4}=\frac{184}{-8} =-23 $
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